Distance between Sevastopol and Lazarevskoye
Distance between Sevastopol and Lazarevskoye is 468.89 km. This distance is equal to 291.35 miles, and 253.01 nautical miles.
The distance line on map shows distance from Sevastopol to Lazarevskoye between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sevastopol to Lazarevskoye,
It takes 0.52 hours to arrive.
| Sevastopol | 44.61665 | 33.525367 |
|---|---|---|
| Lazarevskoye | 43.9150254 | 39.3333917 |
| Distance | 468.89 km | 291.35 miles |
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