Distance between Sevastopol and Yablonovsky
Distance between Sevastopol and Yablonovsky is 429.84 km. This distance is equal to 267.09 miles, and 231.94 nautical miles.
The distance line on map shows distance from Sevastopol to Yablonovsky between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sevastopol to Yablonovsky,
It takes 0.48 hours to arrive.
| Sevastopol | 44.61665 | 33.525367 |
|---|---|---|
| Yablonovsky | 44.9833333 | 38.95 |
| Distance | 429.84 km | 267.09 miles |
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