Distance from Searcy to Midwest City
Distance from Searcy to Midwest City is 515 kilometers. This air travel distance is equal to 320 miles.
The air travel (bird fly) shortest distance between Searcy and Midwest City is 515 km or 320 miles.
If you travel with an airplane (which has average speed of 560 miles) from Searcy to Midwest City, It takes 0.57 hours to arrive.
Searcy
Searcy is located in United States.
| GPS Coordinates (DMS) | 35° 15´ 2.3040'' N 91° 44´ 10.5000'' W |
|---|---|
| Latitude | 35.25064 |
| Longitude | -91.73625 |
| Altitude | 82 m |
| Country | United States |
Searcy Distances to Cities
| Searcy | Distance |
|---|---|
| Distance from Searcy to Tulsa | 398 km |
| Distance from Searcy to Starkville | 334 km |
| Distance from Searcy to Farmers Branch | 541 km |
| Distance from Searcy to Dallas | 542 km |
| Distance from Searcy to Oklahoma City | 526 km |
Midwest City
Midwest City is located in United States.
| GPS Coordinates | 35° 26´ 58.2360'' N 97° 23´ 48.1200'' W |
|---|---|
| Latitude | 35.44951 |
| Longitude | -97.39670 |
| Altitude | 386 m |
| Country | United States |
Midwest City Distances to Cities
| Midwest City | Distance |
|---|---|
| Distance from Midwest City to Oklahoma City | 11 km |
| Distance from Midwest City to Tahlequah | 226 km |
| Distance from Midwest City to Tulsa | 149 km |
| Distance from Midwest City to Mustang | 31 km |
| Distance from Midwest City to Denison | 204 km |