Distance from Sayreville Junction to Seaford
Distance from Sayreville Junction to Seaford is 75 kilometers. This air travel distance is equal to 47 miles.
The air travel (bird fly) shortest distance between Sayreville Junction and Seaford is 75 km or 47 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sayreville Junction to Seaford, It takes 0.08 hours to arrive.
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates (DMS) | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |
Sayreville Junction Distances to Cities
Seaford
Seaford is located in United States.
| GPS Coordinates | 40° 39´ 57.3480'' N 73° 29´ 17.4480'' W |
|---|---|
| Latitude | 40.66593 |
| Longitude | -73.48818 |
| Altitude | 5 m |
| Country | United States |
Seaford Distances to Cities
| Seaford | Distance |
|---|---|
| Distance from Seaford to Middletown Ri | 209 km |
| Distance from Seaford to Los Angeles | 3,988 km |
| Distance from Seaford to Selden | 44 km |
| Distance from Seaford to Bridgewater | 98 km |
| Distance from Seaford to Huntington Beach | 3,986 km |