Distance from East Patchogue to Seaford
Distance from East Patchogue to Seaford is 43 kilometers. This air travel distance is equal to 27 miles.
The air travel (bird fly) shortest distance between East Patchogue and Seaford is 43 km or 27 miles.
If you travel with an airplane (which has average speed of 560 miles) from East Patchogue to Seaford, It takes 0.05 hours to arrive.
East Patchogue
East Patchogue is located in United States.
| GPS Coordinates (DMS) | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
|---|---|
| Latitude | 40.76704 |
| Longitude | -72.99622 |
| Altitude | 9 m |
| Country | United States |
East Patchogue Distances to Cities
Seaford
Seaford is located in United States.
| GPS Coordinates | 40° 39´ 57.3480'' N 73° 29´ 17.4480'' W |
|---|---|
| Latitude | 40.66593 |
| Longitude | -73.48818 |
| Altitude | 5 m |
| Country | United States |
Seaford Distances to Cities
| Seaford | Distance |
|---|---|
| Distance from Seaford to Middletown Ri | 209 km |
| Distance from Seaford to Los Angeles | 3,988 km |
| Distance from Seaford to Selden | 44 km |
| Distance from Seaford to Bridgewater | 98 km |
| Distance from Seaford to Huntington Beach | 3,986 km |