Distance from Clarksburg to Sayreville
Distance from Clarksburg to Sayreville is 528 kilometers. This air travel distance is equal to 328 miles.
The air travel (bird fly) shortest distance between Clarksburg and Sayreville is 528 km or 328 miles.
If you travel with an airplane (which has average speed of 560 miles) from Clarksburg to Sayreville, It takes 0.59 hours to arrive.
Clarksburg
Clarksburg is located in United States.
| GPS Coordinates (DMS) | 39° 16´ 50.3400'' N 80° 20´ 40.3080'' W |
|---|---|
| Latitude | 39.28065 |
| Longitude | -80.34453 |
| Altitude | 306 m |
| Country | United States |
Clarksburg Distances to Cities
Sayreville
Sayreville is located in United States.
| GPS Coordinates | 40° 27´ 33.3720'' N 74° 21´ 39.5280'' W |
|---|---|
| Latitude | 40.45927 |
| Longitude | -74.36098 |
| Altitude | 24 m |
| Country | United States |
Sayreville Distances to Cities
| Sayreville | Distance |
|---|---|
| Distance from Sayreville to Monroe Wa | 3,833 km |
| Distance from Sayreville to Merrick | 72 km |
| Distance from Sayreville to Seaford | 77 km |
| Distance from Sayreville to South Orange | 33 km |
| Distance from Sayreville to Mckeesport | 467 km |