Distance from Severna Park to Sayreville Junction
Distance from Severna Park to Sayreville Junction is 245 kilometers. This air travel distance is equal to 152 miles.
The air travel (bird fly) shortest distance between Severna Park and Sayreville Junction is 245 km or 152 miles.
If you travel with an airplane (which has average speed of 560 miles) from Severna Park to Sayreville Junction, It takes 0.27 hours to arrive.
Severna Park
Severna Park is located in United States.
| GPS Coordinates (DMS) | 39° 4´ 13.4040'' N 76° 32´ 42.8640'' W |
|---|---|
| Latitude | 39.07039 |
| Longitude | -76.54524 |
| Altitude | 14 m |
| Country | United States |
Severna Park Distances to Cities
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |