Distance from Searcy to Sapulpa
Distance from Searcy to Sapulpa is 405 kilometers. This air travel distance is equal to 252 miles.
The air travel (bird fly) shortest distance between Searcy and Sapulpa is 405 km or 252 miles.
If you travel with an airplane (which has average speed of 560 miles) from Searcy to Sapulpa, It takes 0.45 hours to arrive.
Searcy
Searcy is located in United States.
| GPS Coordinates (DMS) | 35° 15´ 2.3040'' N 91° 44´ 10.5000'' W |
|---|---|
| Latitude | 35.25064 |
| Longitude | -91.73625 |
| Altitude | 82 m |
| Country | United States |
Searcy Distances to Cities
| Searcy | Distance |
|---|---|
| Distance from Searcy to Tulsa | 398 km |
| Distance from Searcy to Starkville | 334 km |
| Distance from Searcy to Farmers Branch | 541 km |
| Distance from Searcy to Dallas | 542 km |
| Distance from Searcy to Oklahoma City | 526 km |
Sapulpa
Sapulpa is located in United States.
| GPS Coordinates | 35° 59´ 55.3200'' N 96° 6´ 51.0120'' W |
|---|---|
| Latitude | 35.99870 |
| Longitude | -96.11417 |
| Altitude | 223 m |
| Country | United States |
Sapulpa Distances to Cities
| Sapulpa | Distance |
|---|---|
| Distance from Sapulpa to Little Elm | 324 km |
| Distance from Sapulpa to Yukon | 159 km |
| Distance from Sapulpa to Memphis | 558 km |
| Distance from Sapulpa to Colorado Springs | 832 km |
| Distance from Sapulpa to Amarillo | 525 km |