Distance from Sapucaia to Pindamonhangaba
Distance from Sapucaia to Pindamonhangaba is 953 kilometers. This air travel distance is equal to 592 miles.
The air travel (bird fly) shortest distance between Sapucaia and Pindamonhangaba is 953 km or 592 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sapucaia to Pindamonhangaba, It takes 1.06 hours to arrive.
Sapucaia
Sapucaia is located in Brazil.
| GPS Coordinates (DMS) | 29° 49´ 59.9880'' S 51° 8´ 60.0000'' W |
|---|---|
| Latitude | -29.83333 |
| Longitude | -51.15000 |
| Altitude | 37 m |
| Country | Brazil |
Sapucaia Distances to Cities
| Sapucaia | Distance |
|---|---|
| Distance from Sapucaia to Mogi Mirim | 921 km |
| Distance from Sapucaia to Duque De Caxias | 1,105 km |
| Distance from Sapucaia to Itabira | 1,386 km |
| Distance from Sapucaia to Ponte Nova | 1,333 km |
| Distance from Sapucaia to Lapa | 472 km |
Pindamonhangaba
Pindamonhangaba is located in Brazil.
| GPS Coordinates | 22° 55´ 26.0040'' S 45° 27´ 42.0120'' W |
|---|---|
| Latitude | -22.92389 |
| Longitude | -45.46167 |
| Altitude | 562 m |
| Country | Brazil |
Pindamonhangaba Distances to Cities
| Pindamonhangaba | Distance |
|---|---|
| Distance from Pindamonhangaba to Lavras | 192 km |
| Distance from Pindamonhangaba to Paraguacu | 155 km |
| Distance from Pindamonhangaba to Indaiatuba | 180 km |
| Distance from Pindamonhangaba to Aracatuba | 547 km |
| Distance from Pindamonhangaba to Cajati | 337 km |