Distance from Sapucaia to Manhuacu
Distance from Sapucaia to Manhuaçu is 1,403 kilometers. This air travel distance is equal to 872 miles.
The air travel (bird fly) shortest distance between Sapucaia and Manhuaçu is 1,403 km or 872 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sapucaia to Manhuacu, It takes 1.56 hours to arrive.
Sapucaia
Sapucaia is located in Brazil.
| GPS Coordinates (DMS) | 29° 49´ 59.9880'' S 51° 8´ 60.0000'' W |
|---|---|
| Latitude | -29.83333 |
| Longitude | -51.15000 |
| Altitude | 37 m |
| Country | Brazil |
Sapucaia Distances to Cities
| Sapucaia | Distance |
|---|---|
| Distance from Sapucaia to Mogi Mirim | 921 km |
| Distance from Sapucaia to Duque De Caxias | 1,105 km |
| Distance from Sapucaia to Itabira | 1,386 km |
| Distance from Sapucaia to Ponte Nova | 1,333 km |
| Distance from Sapucaia to Lapa | 472 km |
Manhuacu
Manhuacu is located in Brazil.
| GPS Coordinates | 20° 15´ 29.0160'' S 42° 2´ 0.9960'' W |
|---|---|
| Latitude | -20.25806 |
| Longitude | -42.03361 |
| Altitude | 641 m |
| Country | Brazil |
Manhuaçu Distances to Cities
| Manhuaçu | Distance |
|---|---|
| Distance from Manhuacu to Belo Horizonte | 203 km |
| Distance from Manhuacu to Campos | 181 km |
| Distance from Manhuacu to Barroso | 227 km |
| Distance from Manhuacu to Formiga | 355 km |
| Distance from Manhuacu to Ipaba | 102 km |