Distance from Sandy Springs to Jefferson
Distance from Sandy Springs to Jefferson is 846 kilometers. This air travel distance is equal to 526 miles.
The air travel (bird fly) shortest distance between Sandy Springs and Jefferson is 846 km or 526 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sandy Springs to Jefferson, It takes 0.94 hours to arrive.
Sandy Springs
Sandy Springs is located in United States.
| GPS Coordinates (DMS) | 33° 55´ 27.3720'' N 84° 22´ 42.7440'' W |
|---|---|
| Latitude | 33.92427 |
| Longitude | -84.37854 |
| Altitude | 333 m |
| Country | United States |
Sandy Springs Distances to Cities
| Sandy Springs | Distance |
|---|---|
| Distance from Sandy Springs to Tucker | 17 km |
| Distance from Sandy Springs to Glendale Az | 2,569 km |
| Distance from Sandy Springs to North Augusta | 229 km |
| Distance from Sandy Springs to Savannah | 368 km |
| Distance from Sandy Springs to Nashville | 332 km |
Jefferson
Jefferson is located in United States.
| GPS Coordinates | 38° 51´ 52.4160'' N 77° 11´ 15.9360'' W |
|---|---|
| Latitude | 38.86456 |
| Longitude | -77.18776 |
| Altitude | 106 m |
| Country | United States |
Jefferson Distances to Cities
| Jefferson | Distance |
|---|---|
| Distance from Jefferson to Wayne Mi | 647 km |
| Distance from Jefferson to Winthrop | 654 km |
| Distance from Jefferson to San Pedro | 3,704 km |
| Distance from Jefferson to New Berlin | 1,026 km |
| Distance from Jefferson to Frankfort Il | 953 km |