Distance from Cleveland Heights to Sandusky
Distance from Cleveland Heights to Sandusky is 97 kilometers. This air travel distance is equal to 60 miles.
The air travel (bird fly) shortest distance between Cleveland Heights and Sandusky is 97 km or 60 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cleveland Heights to Sandusky, It takes 0.11 hours to arrive.
Cleveland Heights
Cleveland Heights is located in United States.
| GPS Coordinates (DMS) | 41° 31´ 12.1800'' N 81° 33´ 22.4640'' W |
|---|---|
| Latitude | 41.52005 |
| Longitude | -81.55624 |
| Altitude | 288 m |
| Country | United States |
Cleveland Heights Distances to Cities
| Cleveland Heights | Distance |
|---|---|
| Distance from Cleveland Heights to Lemont | 538 km |
| Distance from Cleveland Heights to Libertyville | 537 km |
| Distance from Cleveland Heights to Avon | 41 km |
| Distance from Cleveland Heights to Elmhurst | 533 km |
| Distance from Cleveland Heights to Redford | 173 km |
Sandusky
Sandusky is located in United States.
| GPS Coordinates | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
|---|---|
| Latitude | 41.44894 |
| Longitude | -82.70796 |
| Altitude | 183 m |
| Country | United States |
Sandusky Distances to Cities
| Sandusky | Distance |
|---|---|
| Distance from Sandusky to South Euclid | 100 km |
| Distance from Sandusky to Waukesha | 488 km |
| Distance from Sandusky to Pittsburgh | 254 km |
| Distance from Sandusky to Tucson | 2,702 km |
| Distance from Sandusky to Janesville | 540 km |