Distance from Oakley to San Leandro
Distance from Oakley to San Leandro is 49 kilometers. This air travel distance is equal to 30 miles.
The air travel (bird fly) shortest distance between Oakley and San Leandro is 49 km or 30 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oakley to San Leandro, It takes 0.05 hours to arrive.
Oakley
Oakley is located in United States.
| GPS Coordinates (DMS) | 37° 59´ 50.7120'' N 121° 42´ 44.8200'' W |
|---|---|
| Latitude | 37.99742 |
| Longitude | -121.71245 |
| Altitude | 5 m |
| Country | United States |
Oakley Distances to Cities
San Leandro
San Leandro is located in United States.
| GPS Coordinates | 37° 43´ 29.7480'' N 122° 9´ 21.8880'' W |
|---|---|
| Latitude | 37.72493 |
| Longitude | -122.15608 |
| Altitude | 19 m |
| Country | United States |