Distance from Antioch to San Leandro
Distance from Antioch to San Leandro is 44 kilometers. This air travel distance is equal to 27 miles.
The air travel (bird fly) shortest distance between Antioch and San Leandro is 44 km or 27 miles.
If you travel with an airplane (which has average speed of 560 miles) from Antioch to San Leandro, It takes 0.05 hours to arrive.
Antioch
Antioch is located in United States.
| GPS Coordinates (DMS) | 38° 0´ 17.7120'' N 121° 48´ 20.8440'' W |
|---|---|
| Latitude | 38.00492 |
| Longitude | -121.80579 |
| Altitude | 13 m |
| Country | United States |
Antioch Distances to Cities
San Leandro
San Leandro is located in United States.
| GPS Coordinates | 37° 43´ 29.7480'' N 122° 9´ 21.8880'' W |
|---|---|
| Latitude | 37.72493 |
| Longitude | -122.15608 |
| Altitude | 19 m |
| Country | United States |