Distance from San Jacinto to Walnut Park
Distance from San Jacinto to Walnut Park is 119 kilometers. This air travel distance is equal to 74 miles.
The air travel (bird fly) shortest distance between San Jacinto and Walnut Park is 119 km or 74 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Jacinto to Walnut Park, It takes 0.13 hours to arrive.
San Jacinto
San Jacinto is located in United States.
| GPS Coordinates (DMS) | 33° 47´ 2.0760'' N 116° 57´ 31.1040'' W |
|---|---|
| Latitude | 33.78391 |
| Longitude | -116.95864 |
| Altitude | 480 m |
| Country | United States |
San Jacinto Distances to Cities
Walnut Park
Walnut Park is located in United States.
| GPS Coordinates | 33° 58´ 5.0520'' N 118° 13´ 30.2520'' W |
|---|---|
| Latitude | 33.96807 |
| Longitude | -118.22507 |
| Altitude | 48 m |
| Country | United States |
Walnut Park Distances to Cities
| Walnut Park | Distance |
|---|---|
| Distance from Walnut Park to West Covina | 29 km |
| Distance from Walnut Park to Whittier | 18 km |
| Distance from Walnut Park to Yucaipa | 109 km |
| Distance from Walnut Park to Apache Junction | 622 km |
| Distance from Walnut Park to Bremerton | 1,555 km |