Distance from Lawndale to San Jacinto
Distance from Lawndale to San Jacinto is 130 kilometers. This air travel distance is equal to 81 miles.
The air travel (bird fly) shortest distance between Lawndale and San Jacinto is 130 km or 81 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lawndale to San Jacinto, It takes 0.14 hours to arrive.
Lawndale
Lawndale is located in United States.
| GPS Coordinates (DMS) | 33° 53´ 14.0640'' N 118° 21´ 9.2520'' W |
|---|---|
| Latitude | 33.88724 |
| Longitude | -118.35257 |
| Altitude | 19 m |
| Country | United States |
Lawndale Distances to Cities
| Lawndale | Distance |
|---|---|
| Distance from Lawndale to Los Angeles | 21 km |
| Distance from Lawndale to Lynwood | 14 km |
| Distance from Lawndale to Paso Robles | 288 km |
| Distance from Lawndale to Temecula | 120 km |
| Distance from Lawndale to Lompoc | 211 km |
San Jacinto
San Jacinto is located in United States.
| GPS Coordinates | 33° 47´ 2.0760'' N 116° 57´ 31.1040'' W |
|---|---|
| Latitude | 33.78391 |
| Longitude | -116.95864 |
| Altitude | 480 m |
| Country | United States |