Distance from San Fernando to Walnut Park
Distance from San Fernando to Walnut Park is 40 kilometers. This air travel distance is equal to 25 miles.
The air travel (bird fly) shortest distance between San Fernando and Walnut Park is 40 km or 25 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Fernando to Walnut Park, It takes 0.04 hours to arrive.
San Fernando
San Fernando is located in United States.
| GPS Coordinates (DMS) | 34° 16´ 55.0200'' N 118° 26´ 20.2920'' W |
|---|---|
| Latitude | 34.28195 |
| Longitude | -118.43897 |
| Altitude | 327 m |
| Country | United States |
San Fernando Distances to Cities
Walnut Park
Walnut Park is located in United States.
| GPS Coordinates | 33° 58´ 5.0520'' N 118° 13´ 30.2520'' W |
|---|---|
| Latitude | 33.96807 |
| Longitude | -118.22507 |
| Altitude | 48 m |
| Country | United States |
Walnut Park Distances to Cities
| Walnut Park | Distance |
|---|---|
| Distance from Walnut Park to West Covina | 29 km |
| Distance from Walnut Park to Whittier | 18 km |
| Distance from Walnut Park to Yucaipa | 109 km |
| Distance from Walnut Park to Apache Junction | 622 km |
| Distance from Walnut Park to Bremerton | 1,555 km |