Distance from Boynton Beach to Safety Harbor
Distance from Boynton Beach to Safety Harbor is 307 kilometers. This air travel distance is equal to 191 miles.
The air travel (bird fly) shortest distance between Boynton Beach and Safety Harbor is 307 km or 191 miles.
If you travel with an airplane (which has average speed of 560 miles) from Boynton Beach to Safety Harbor, It takes 0.34 hours to arrive.
Boynton Beach
Boynton Beach is located in United States.
| GPS Coordinates (DMS) | 26° 31´ 31.2600'' N 80° 3´ 59.1480'' W |
|---|---|
| Latitude | 26.52535 |
| Longitude | -80.06643 |
| Altitude | 11 m |
| Country | United States |
Boynton Beach Distances to Cities
Safety Harbor
Safety Harbor is located in United States.
| GPS Coordinates | 27° 59´ 27.0600'' N 82° 41´ 35.3760'' W |
|---|---|
| Latitude | 27.99085 |
| Longitude | -82.69316 |
| Altitude | 12 m |
| Country | United States |
Safety Harbor Distances to Cities
| Safety Harbor | Distance |
|---|---|
| Distance from Safety Harbor to New Orleans | 752 km |
| Distance from Safety Harbor to Tempe | 2,853 km |
| Distance from Safety Harbor to Chicago | 1,602 km |
| Distance from Safety Harbor to Town N Country | 12 km |
| Distance from Safety Harbor to Dallas | 1,455 km |