Distance from Lake Charles to Rosenberg
Distance from Lake Charles to Rosenberg is 262 kilometers. This air travel distance is equal to 163 miles.
The air travel (bird fly) shortest distance between Lake Charles and Rosenberg is 262 km or 163 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lake Charles to Rosenberg, It takes 0.29 hours to arrive.
Lake Charles
Lake Charles is located in United States.
| GPS Coordinates (DMS) | 30° 12´ 47.1240'' N 93° 12´ 15.8400'' W |
|---|---|
| Latitude | 30.21309 |
| Longitude | -93.20440 |
| Altitude | 6 m |
| Country | United States |
Lake Charles Distances to Cities
| Lake Charles | Distance |
|---|---|
| Distance from Lake Charles to Houston | 214 km |
| Distance from Lake Charles to Los Angeles | 2,394 km |
| Distance from Lake Charles to New Iberia | 136 km |
| Distance from Lake Charles to Galveston | 184 km |
| Distance from Lake Charles to Charlotte | 1,284 km |
Rosenberg
Rosenberg is located in United States.
| GPS Coordinates | 29° 33´ 25.8480'' N 95° 48´ 30.8160'' W |
|---|---|
| Latitude | 29.55718 |
| Longitude | -95.80856 |
| Altitude | 35 m |
| Country | United States |
Rosenberg Distances to Cities
| Rosenberg | Distance |
|---|---|
| Distance from Rosenberg to Holland | 1,705 km |
| Distance from Rosenberg to Rotterdam | 2,440 km |
| Distance from Rosenberg to San Antonio | 261 km |
| Distance from Rosenberg to Stafford | 25 km |
| Distance from Rosenberg to Somerset Ma | 2,599 km |