Distance from Sayreville Junction to Roosevelt
Distance from Sayreville Junction to Roosevelt is 67 kilometers. This air travel distance is equal to 42 miles.
The air travel (bird fly) shortest distance between Sayreville Junction and Roosevelt is 67 km or 42 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sayreville Junction to Roosevelt, It takes 0.07 hours to arrive.
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates (DMS) | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |
Sayreville Junction Distances to Cities
Roosevelt
Roosevelt is located in United States.
| GPS Coordinates | 40° 40´ 43.3560'' N 73° 35´ 20.4720'' W |
|---|---|
| Latitude | 40.67871 |
| Longitude | -73.58902 |
| Altitude | 12 m |
| Country | United States |
Roosevelt Distances to Cities
| Roosevelt | Distance |
|---|---|
| Distance from Roosevelt to Wantagh | 7 km |
| Distance from Roosevelt to Rye | 34 km |
| Distance from Roosevelt to Seaford | 9 km |
| Distance from Roosevelt to Phoenix | 3,486 km |
| Distance from Roosevelt to West Islip | 24 km |