Distance from East Patchogue to Roosevelt
Distance from East Patchogue to Roosevelt is 51 kilometers. This air travel distance is equal to 32 miles.
The air travel (bird fly) shortest distance between East Patchogue and Roosevelt is 51 km or 32 miles.
If you travel with an airplane (which has average speed of 560 miles) from East Patchogue to Roosevelt, It takes 0.06 hours to arrive.
East Patchogue
East Patchogue is located in United States.
| GPS Coordinates (DMS) | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
|---|---|
| Latitude | 40.76704 |
| Longitude | -72.99622 |
| Altitude | 9 m |
| Country | United States |
East Patchogue Distances to Cities
Roosevelt
Roosevelt is located in United States.
| GPS Coordinates | 40° 40´ 43.3560'' N 73° 35´ 20.4720'' W |
|---|---|
| Latitude | 40.67871 |
| Longitude | -73.58902 |
| Altitude | 12 m |
| Country | United States |
Roosevelt Distances to Cities
| Roosevelt | Distance |
|---|---|
| Distance from Roosevelt to Wantagh | 7 km |
| Distance from Roosevelt to Rye | 34 km |
| Distance from Roosevelt to Seaford | 9 km |
| Distance from Roosevelt to Phoenix | 3,486 km |
| Distance from Roosevelt to West Islip | 24 km |