Distance from Rocklin to San Leandro
Distance from Rocklin to San Leandro is 143 kilometers. This air travel distance is equal to 89 miles.
The air travel (bird fly) shortest distance between Rocklin and San Leandro is 143 km or 89 miles.
If you travel with an airplane (which has average speed of 560 miles) from Rocklin to San Leandro, It takes 0.16 hours to arrive.
Rocklin
Rocklin is located in United States.
| GPS Coordinates (DMS) | 38° 47´ 26.6280'' N 121° 14´ 8.8080'' W |
|---|---|
| Latitude | 38.79073 |
| Longitude | -121.23578 |
| Altitude | 76 m |
| Country | United States |
Rocklin Distances to Cities
San Leandro
San Leandro is located in United States.
| GPS Coordinates | 37° 43´ 29.7480'' N 122° 9´ 21.8880'' W |
|---|---|
| Latitude | 37.72493 |
| Longitude | -122.15608 |
| Altitude | 19 m |
| Country | United States |