Distance from Reynoldsburg to Garfield Heights
Distance from Reynoldsburg to Garfield Heights is 192 kilometers. This air travel distance is equal to 119 miles.
The air travel (bird fly) shortest distance between Reynoldsburg and Garfield Heights is 192 km or 119 miles.
If you travel with an airplane (which has average speed of 560 miles) from Reynoldsburg to Garfield Heights, It takes 0.21 hours to arrive.
Reynoldsburg
Reynoldsburg is located in United States.
| GPS Coordinates (DMS) | 39° 57´ 17.2440'' N 82° 48´ 43.6320'' W |
|---|---|
| Latitude | 39.95479 |
| Longitude | -82.81212 |
| Altitude | 266 m |
| Country | United States |
Reynoldsburg Distances to Cities
| Reynoldsburg | Distance |
|---|---|
| Distance from Reynoldsburg to Jamaica Plain | 1,015 km |
| Distance from Reynoldsburg to Lincolnia | 504 km |
| Distance from Reynoldsburg to Boardman | 217 km |
| Distance from Reynoldsburg to Dublin Oh | 30 km |
| Distance from Reynoldsburg to Janesville | 601 km |
Garfield Heights
Garfield Heights is located in United States.
| GPS Coordinates | 41° 25´ 1.2000'' N 81° 36´ 21.4560'' W |
|---|---|
| Latitude | 41.41700 |
| Longitude | -81.60596 |
| Altitude | 290 m |
| Country | United States |