Distance from Secaucus to Port Washington
Distance from Secaucus to Port Washington is 31 kilometers. This air travel distance is equal to 19 miles.
The air travel (bird fly) shortest distance between Secaucus and Port Washington is 31 km or 19 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to Port Washington, It takes 0.03 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
Port Washington
Port Washington is located in United States.
| GPS Coordinates | 40° 49´ 32.3760'' N 73° 41´ 53.4840'' W |
|---|---|
| Latitude | 40.82566 |
| Longitude | -73.69819 |
| Altitude | 33 m |
| Country | United States |