Distance from Point Pleasant to Secaucus
Distance from Point Pleasant to Secaucus is 78 kilometers. This air travel distance is equal to 48 miles.
The air travel (bird fly) shortest distance between Point Pleasant and Secaucus is 78 km or 48 miles.
If you travel with an airplane (which has average speed of 560 miles) from Point Pleasant to Secaucus, It takes 0.09 hours to arrive.
Point Pleasant
Point Pleasant is located in United States.
| GPS Coordinates (DMS) | 40° 4´ 59.4120'' N 74° 4´ 5.4840'' W |
|---|---|
| Latitude | 40.08317 |
| Longitude | -74.06819 |
| Altitude | 7 m |
| Country | United States |
Point Pleasant Distances to Cities
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |