Distance from Petersburg to Savage
Distance from Petersburg to Savage is 1,577 kilometers. This air travel distance is equal to 980 miles.
The air travel (bird fly) shortest distance between Petersburg and Savage is 1,577 km or 980 miles.
If you travel with an airplane (which has average speed of 560 miles) from Petersburg to Savage, It takes 1.75 hours to arrive.
Petersburg
Petersburg is located in United States.
GPS Coordinates (DMS) | 37° 13´ 40.5480'' N 77° 24´ 6.9480'' W |
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Latitude | 37.22793 |
Longitude | -77.40193 |
Altitude | 22 m |
Country | United States |
Petersburg Distances to Cities
Petersburg | Distance |
---|---|
Distance from Petersburg to Virginia Beach | 133 km |
Distance from Petersburg to Beckley | 340 km |
Distance from Petersburg to Staunton | 179 km |
Distance from Petersburg to Roanoke | 225 km |
Distance from Petersburg to Pampa | 2,117 km |
Savage
Savage is located in United States.
GPS Coordinates | 44° 46´ 44.8680'' N 93° 20´ 10.8240'' W |
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Latitude | 44.77913 |
Longitude | -93.33634 |
Altitude | 216 m |
Country | United States |
Savage Distances to Cities
Savage | Distance |
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Distance from Savage to Rye | 1,656 km |
Distance from Savage to Lyndhurst | 1,628 km |
Distance from Savage to Summit | 1,613 km |
Distance from Savage to Wooster | 1,031 km |
Distance from Savage to Colonia | 1,624 km |