Distance from Christiansburg to Petersburg
Distance from Christiansburg to Petersburg is 267 kilometers. This air travel distance is equal to 166 miles.
The air travel (bird fly) shortest distance between Christiansburg and Petersburg is 267 km or 166 miles.
If you travel with an airplane (which has average speed of 560 miles) from Christiansburg to Petersburg, It takes 0.3 hours to arrive.
Christiansburg
Christiansburg is located in United States.
| GPS Coordinates (DMS) | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
|---|---|
| Latitude | 37.12985 |
| Longitude | -80.40894 |
| Altitude | 637 m |
| Country | United States |
Christiansburg Distances to Cities
| Christiansburg | Distance |
|---|---|
| Distance from Christiansburg to Virginia Beach | 396 km |
| Distance from Christiansburg to Los Angeles | 3,423 km |
| Distance from Christiansburg to Roanoke | 44 km |
| Distance from Christiansburg to Elko | 3,070 km |
| Distance from Christiansburg to Tucson | 2,837 km |
Petersburg
Petersburg is located in United States.
| GPS Coordinates | 37° 13´ 40.5480'' N 77° 24´ 6.9480'' W |
|---|---|
| Latitude | 37.22793 |
| Longitude | -77.40193 |
| Altitude | 22 m |
| Country | United States |
Petersburg Distances to Cities
| Petersburg | Distance |
|---|---|
| Distance from Petersburg to Virginia Beach | 133 km |
| Distance from Petersburg to Beckley | 340 km |
| Distance from Petersburg to Staunton | 179 km |
| Distance from Petersburg to Roanoke | 225 km |
| Distance from Petersburg to Pampa | 2,117 km |