Distance from Sayreville Junction to Peekskill
Distance from Sayreville Junction to Peekskill is 98 kilometers. This air travel distance is equal to 61 miles.
The air travel (bird fly) shortest distance between Sayreville Junction and Peekskill is 98 km or 61 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sayreville Junction to Peekskill, It takes 0.11 hours to arrive.
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates (DMS) | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |
Sayreville Junction Distances to Cities
Peekskill
Peekskill is located in United States.
| GPS Coordinates | 41° 17´ 24.3240'' N 73° 55´ 13.5120'' W |
|---|---|
| Latitude | 41.29009 |
| Longitude | -73.92042 |
| Altitude | 49 m |
| Country | United States |
Peekskill Distances to Cities
| Peekskill | Distance |
|---|---|
| Distance from Peekskill to Rye | 40 km |
| Distance from Peekskill to Wantagh | 76 km |
| Distance from Peekskill to Scarsdale | 34 km |
| Distance from Peekskill to Port Washington | 55 km |
| Distance from Peekskill to South Hill | 3,855 km |