Distance from Parker to San Angelo
Distance from Parker to San Angelo is 976 kilometers. This air travel distance is equal to 606 miles.
The air travel (bird fly) shortest distance between Parker and San Angelo is 976 km or 606 miles.
If you travel with an airplane (which has average speed of 560 miles) from Parker to San Angelo, It takes 1.08 hours to arrive.
Parker
Parker is located in United States.
| GPS Coordinates (DMS) | 39° 31´ 6.9600'' N 104° 45´ 40.8960'' W |
|---|---|
| Latitude | 39.51860 |
| Longitude | -104.76136 |
| Altitude | 1795 m |
| Country | United States |
Parker Distances to Cities
| Parker | Distance |
|---|---|
| Distance from Parker to Santa Fe | 438 km |
| Distance from Parker to Lubbock | 709 km |
| Distance from Parker to Hobbs | 770 km |
| Distance from Parker to Amarillo | 543 km |
| Distance from Parker to Four Corners Or | 1,616 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |