Distance from Oakton to Sayreville Junction
Distance from Oakton to Sayreville Junction is 310 kilometers. This air travel distance is equal to 193 miles.
The air travel (bird fly) shortest distance between Oakton and Sayreville Junction is 310 km or 193 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oakton to Sayreville Junction, It takes 0.34 hours to arrive.
Oakton
Oakton is located in United States.
| GPS Coordinates (DMS) | 38° 52´ 51.4200'' N 77° 18´ 2.9520'' W |
|---|---|
| Latitude | 38.88095 |
| Longitude | -77.30082 |
| Altitude | 128 m |
| Country | United States |
Oakton Distances to Cities
| Oakton | Distance |
|---|---|
| Distance from Oakton to South River | 305 km |
| Distance from Oakton to Fort Lee | 359 km |
| Distance from Oakton to New London | 521 km |
| Distance from Oakton to Tysons Corner | 7 km |
| Distance from Oakton to Auburn Wa | 3,720 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |