Distance from Norton to Secaucus
Distance from Norton to Secaucus is 273 kilometers. This air travel distance is equal to 170 miles.
The air travel (bird fly) shortest distance between Norton and Secaucus is 273 km or 170 miles.
If you travel with an airplane (which has average speed of 560 miles) from Norton to Secaucus, It takes 0.3 hours to arrive.
Norton
Norton is located in United States.
| GPS Coordinates (DMS) | 41° 58´ 0.3720'' N 71° 11´ 13.1640'' W |
|---|---|
| Latitude | 41.96677 |
| Longitude | -71.18699 |
| Altitude | 9 m |
| Country | United States |
Norton Distances to Cities
| Norton | Distance |
|---|---|
| Distance from Norton to Rye | 236 km |
| Distance from Norton to Waltham | 46 km |
| Distance from Norton to Woonsocket | 27 km |
| Distance from Norton to Hudson | 858 km |
| Distance from Norton to Richfield | 1,812 km |
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |