Distance from Norton to Sayreville Junction
Distance from Norton to Sayreville Junction is 312 kilometers. This air travel distance is equal to 194 miles.
The air travel (bird fly) shortest distance between Norton and Sayreville Junction is 312 km or 194 miles.
If you travel with an airplane (which has average speed of 560 miles) from Norton to Sayreville Junction, It takes 0.35 hours to arrive.
Norton
Norton is located in United States.
| GPS Coordinates (DMS) | 41° 58´ 0.3720'' N 71° 11´ 13.1640'' W |
|---|---|
| Latitude | 41.96677 |
| Longitude | -71.18699 |
| Altitude | 9 m |
| Country | United States |
Norton Distances to Cities
| Norton | Distance |
|---|---|
| Distance from Norton to Rye | 236 km |
| Distance from Norton to Waltham | 46 km |
| Distance from Norton to Woonsocket | 27 km |
| Distance from Norton to Hudson | 858 km |
| Distance from Norton to Richfield | 1,812 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |