Distance from Secaucus to North Providence
Distance from Secaucus to North Providence is 247 kilometers. This air travel distance is equal to 153 miles.
The air travel (bird fly) shortest distance between Secaucus and North Providence is 247 km or 153 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to North Providence, It takes 0.27 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
North Providence
North Providence is located in United States.
| GPS Coordinates | 41° 51´ 0.3600'' N 71° 27´ 58.2120'' W |
|---|---|
| Latitude | 41.85010 |
| Longitude | -71.46617 |
| Altitude | 39 m |
| Country | United States |