Distance from North Olmsted to Sandusky
Distance from North Olmsted to Sandusky is 66 kilometers. This air travel distance is equal to 41 miles.
The air travel (bird fly) shortest distance between North Olmsted and Sandusky is 66 km or 41 miles.
If you travel with an airplane (which has average speed of 560 miles) from North Olmsted to Sandusky, It takes 0.07 hours to arrive.
North Olmsted
North Olmsted is located in United States.
| GPS Coordinates (DMS) | 41° 24´ 56.1600'' N 81° 55´ 24.4920'' W |
|---|---|
| Latitude | 41.41560 |
| Longitude | -81.92347 |
| Altitude | 231 m |
| Country | United States |
North Olmsted Distances to Cities
Sandusky
Sandusky is located in United States.
| GPS Coordinates | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
|---|---|
| Latitude | 41.44894 |
| Longitude | -82.70796 |
| Altitude | 183 m |
| Country | United States |
Sandusky Distances to Cities
| Sandusky | Distance |
|---|---|
| Distance from Sandusky to South Euclid | 100 km |
| Distance from Sandusky to Waukesha | 488 km |
| Distance from Sandusky to Pittsburgh | 254 km |
| Distance from Sandusky to Tucson | 2,702 km |
| Distance from Sandusky to Janesville | 540 km |