Distance from Secaucus to North Massapequa
Distance from Secaucus to North Massapequa is 51 kilometers. This air travel distance is equal to 32 miles.
The air travel (bird fly) shortest distance between Secaucus and North Massapequa is 51 km or 32 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to North Massapequa, It takes 0.06 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
North Massapequa
North Massapequa is located in United States.
| GPS Coordinates | 40° 42´ 3.3480'' N 73° 27´ 43.4520'' W |
|---|---|
| Latitude | 40.70093 |
| Longitude | -73.46207 |
| Altitude | 17 m |
| Country | United States |