Distance from Searcy to Norman
Distance from Searcy to Norman is 519 kilometers. This air travel distance is equal to 322 miles.
The air travel (bird fly) shortest distance between Searcy and Norman is 519 km or 322 miles.
If you travel with an airplane (which has average speed of 560 miles) from Searcy to Norman, It takes 0.58 hours to arrive.
Searcy
Searcy is located in United States.
| GPS Coordinates (DMS) | 35° 15´ 2.3040'' N 91° 44´ 10.5000'' W |
|---|---|
| Latitude | 35.25064 |
| Longitude | -91.73625 |
| Altitude | 82 m |
| Country | United States |
Searcy Distances to Cities
| Searcy | Distance |
|---|---|
| Distance from Searcy to Tulsa | 398 km |
| Distance from Searcy to Starkville | 334 km |
| Distance from Searcy to Farmers Branch | 541 km |
| Distance from Searcy to Dallas | 542 km |
| Distance from Searcy to Oklahoma City | 526 km |
Norman
Norman is located in United States.
| GPS Coordinates | 35° 13´ 21.2520'' N 97° 26´ 22.1280'' W |
|---|---|
| Latitude | 35.22257 |
| Longitude | -97.43948 |
| Altitude | 361 m |
| Country | United States |
Norman Distances to Cities
| Norman | Distance |
|---|---|
| Distance from Norman to Oklahoma City | 28 km |
| Distance from Norman to Lubbock | 445 km |
| Distance from Norman to Pampa | 322 km |
| Distance from Norman to Dallas | 277 km |
| Distance from Norman to Tahlequah | 237 km |