Distance from Mount Prospect to Farmington Hills
Distance from Mount Prospect to Farmington Hills is 379 kilometers. This air travel distance is equal to 235 miles.
The air travel (bird fly) shortest distance between Mount Prospect and Farmington Hills is 379 km or 235 miles.
If you travel with an airplane (which has average speed of 560 miles) from Mount Prospect to Farmington Hills, It takes 0.42 hours to arrive.
Mount Prospect
Mount Prospect is located in United States.
| GPS Coordinates (DMS) | 42° 3´ 59.1120'' N 87° 56´ 14.2440'' W |
|---|---|
| Latitude | 42.06642 |
| Longitude | -87.93729 |
| Altitude | 205 m |
| Country | United States |
Mount Prospect Distances to Cities
Farmington Hills
Farmington Hills is located in United States.
| GPS Coordinates | 42° 29´ 7.1160'' N 83° 22´ 37.7760'' W |
|---|---|
| Latitude | 42.48531 |
| Longitude | -83.37716 |
| Altitude | 260 m |
| Country | United States |