Distance from Monrovia to San Jacinto
Distance from Monrovia to San Jacinto is 104 kilometers. This air travel distance is equal to 65 miles.
The air travel (bird fly) shortest distance between Monrovia and San Jacinto is 104 km or 65 miles.
If you travel with an airplane (which has average speed of 560 miles) from Monrovia to San Jacinto, It takes 0.12 hours to arrive.
Monrovia
Monrovia is located in United States.
| GPS Coordinates (DMS) | 34° 8´ 53.0160'' N 117° 59´ 56.2200'' W |
|---|---|
| Latitude | 34.14806 |
| Longitude | -117.99895 |
| Altitude | 176 m |
| Country | United States |
Monrovia Distances to Cities
San Jacinto
San Jacinto is located in United States.
| GPS Coordinates | 33° 47´ 2.0760'' N 116° 57´ 31.1040'' W |
|---|---|
| Latitude | 33.78391 |
| Longitude | -116.95864 |
| Altitude | 480 m |
| Country | United States |