Distance from Secaucus to Mineola
Distance from Secaucus to Mineola is 35 kilometers. This air travel distance is equal to 22 miles.
The air travel (bird fly) shortest distance between Secaucus and Mineola is 35 km or 22 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to Mineola, It takes 0.04 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
Mineola
Mineola is located in United States.
| GPS Coordinates | 40° 44´ 57.3720'' N 73° 38´ 26.4480'' W |
|---|---|
| Latitude | 40.74927 |
| Longitude | -73.64068 |
| Altitude | 36 m |
| Country | United States |