Distance from Savage to Mineola
Distance from Savage to Mineola is 1,668 kilometers. This air travel distance is equal to 1,036 miles.
The air travel (bird fly) shortest distance between Savage and Mineola is 1,668 km or 1,036 miles.
If you travel with an airplane (which has average speed of 560 miles) from Savage to Mineola, It takes 1.85 hours to arrive.
Savage
Savage is located in United States.
| GPS Coordinates (DMS) | 44° 46´ 44.8680'' N 93° 20´ 10.8240'' W |
|---|---|
| Latitude | 44.77913 |
| Longitude | -93.33634 |
| Altitude | 216 m |
| Country | United States |
Savage Distances to Cities
| Savage | Distance |
|---|---|
| Distance from Savage to Rye | 1,656 km |
| Distance from Savage to Lyndhurst | 1,628 km |
| Distance from Savage to Summit | 1,613 km |
| Distance from Savage to Wooster | 1,031 km |
| Distance from Savage to Colonia | 1,624 km |
Mineola
Mineola is located in United States.
| GPS Coordinates | 40° 44´ 57.3720'' N 73° 38´ 26.4480'' W |
|---|---|
| Latitude | 40.74927 |
| Longitude | -73.64068 |
| Altitude | 36 m |
| Country | United States |