Distance from Martinsburg to Secaucus
Distance from Martinsburg to Secaucus is 364 kilometers. This air travel distance is equal to 226 miles.
The air travel (bird fly) shortest distance between Martinsburg and Secaucus is 364 km or 226 miles.
If you travel with an airplane (which has average speed of 560 miles) from Martinsburg to Secaucus, It takes 0.4 hours to arrive.
Martinsburg
Martinsburg is located in United States.
| GPS Coordinates (DMS) | 39° 27´ 22.3560'' N 77° 57´ 50.0040'' W |
|---|---|
| Latitude | 39.45621 |
| Longitude | -77.96389 |
| Altitude | 139 m |
| Country | United States |
Martinsburg Distances to Cities
| Martinsburg | Distance |
|---|---|
| Distance from Martinsburg to Los Angeles | 3,616 km |
| Distance from Martinsburg to Framingham | 635 km |
| Distance from Martinsburg to Steubenville | 250 km |
| Distance from Martinsburg to Pittsburgh | 205 km |
| Distance from Martinsburg to Dix Hills | 422 km |
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |