Distance from Martinsburg to Sayville
Distance from Martinsburg to Sayville is 440 kilometers. This air travel distance is equal to 273 miles.
The air travel (bird fly) shortest distance between Martinsburg and Sayville is 440 km or 273 miles.
If you travel with an airplane (which has average speed of 560 miles) from Martinsburg to Sayville, It takes 0.49 hours to arrive.
Martinsburg
Martinsburg is located in United States.
| GPS Coordinates (DMS) | 39° 27´ 22.3560'' N 77° 57´ 50.0040'' W |
|---|---|
| Latitude | 39.45621 |
| Longitude | -77.96389 |
| Altitude | 139 m |
| Country | United States |
Martinsburg Distances to Cities
| Martinsburg | Distance |
|---|---|
| Distance from Martinsburg to Los Angeles | 3,616 km |
| Distance from Martinsburg to Framingham | 635 km |
| Distance from Martinsburg to Steubenville | 250 km |
| Distance from Martinsburg to Pittsburgh | 205 km |
| Distance from Martinsburg to Dix Hills | 422 km |
Sayville
Sayville is located in United States.
| GPS Coordinates | 40° 44´ 9.3480'' N 73° 4´ 55.4160'' W |
|---|---|
| Latitude | 40.73593 |
| Longitude | -73.08206 |
| Altitude | 9 m |
| Country | United States |