Distance from Secaucus to Lynbrook
Distance from Secaucus to Lynbrook is 36 kilometers. This air travel distance is equal to 22 miles.
The air travel (bird fly) shortest distance between Secaucus and Lynbrook is 36 km or 22 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to Lynbrook, It takes 0.04 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
Lynbrook
Lynbrook is located in United States.
| GPS Coordinates | 40° 39´ 17.3880'' N 73° 40´ 18.4800'' W |
|---|---|
| Latitude | 40.65483 |
| Longitude | -73.67180 |
| Altitude | 8 m |
| Country | United States |