Distance from Lufkin to San Angelo
Distance from Lufkin to San Angelo is 543 kilometers. This air travel distance is equal to 337 miles.
The air travel (bird fly) shortest distance between Lufkin and San Angelo is 543 km or 337 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lufkin to San Angelo, It takes 0.6 hours to arrive.
Lufkin
Lufkin is located in United States.
| GPS Coordinates (DMS) | 31° 20´ 17.6640'' N 94° 43´ 44.7600'' W |
|---|---|
| Latitude | 31.33824 |
| Longitude | -94.72910 |
| Altitude | 99 m |
| Country | United States |
Lufkin Distances to Cities
| Lufkin | Distance |
|---|---|
| Distance from Lufkin to Nacogdoches | 30 km |
| Distance from Lufkin to Waco | 231 km |
| Distance from Lufkin to San Antonio | 419 km |
| Distance from Lufkin to Weatherford | 330 km |
| Distance from Lufkin to Round Rock | 297 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |