Distance from Longmeadow to Sayreville Junction
Distance from Longmeadow to Sayreville Junction is 229 kilometers. This air travel distance is equal to 142 miles.
The air travel (bird fly) shortest distance between Longmeadow and Sayreville Junction is 229 km or 142 miles.
If you travel with an airplane (which has average speed of 560 miles) from Longmeadow to Sayreville Junction, It takes 0.25 hours to arrive.
Longmeadow
Longmeadow is located in United States.
| GPS Coordinates (DMS) | 42° 3´ 0.3600'' N 72° 34´ 58.3320'' W |
|---|---|
| Latitude | 42.05010 |
| Longitude | -72.58287 |
| Altitude | 50 m |
| Country | United States |
Longmeadow Distances to Cities
| Longmeadow | Distance |
|---|---|
| Distance from Longmeadow to South Hill | 3,918 km |
| Distance from Longmeadow to Providence | 100 km |
| Distance from Longmeadow to Holbrook | 144 km |
| Distance from Longmeadow to Marlborough | 91 km |
| Distance from Longmeadow to Bangor | 434 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |