Distance from Sayreville Junction to Lindenhurst
Distance from Sayreville Junction to Lindenhurst is 85 kilometers. This air travel distance is equal to 53 miles.
The air travel (bird fly) shortest distance between Sayreville Junction and Lindenhurst is 85 km or 53 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sayreville Junction to Lindenhurst, It takes 0.09 hours to arrive.
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates (DMS) | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |
Sayreville Junction Distances to Cities
Lindenhurst
Lindenhurst is located in United States.
| GPS Coordinates | 40° 41´ 12.3720'' N 73° 22´ 24.4200'' W |
|---|---|
| Latitude | 40.68677 |
| Longitude | -73.37345 |
| Altitude | 8 m |
| Country | United States |