Distance from Linden to Sayreville Junction
Distance from Linden to Sayreville Junction is 19 kilometers. This air travel distance is equal to 12 miles.
The air travel (bird fly) shortest distance between Linden and Sayreville Junction is 19 km or 12 miles.
If you travel with an airplane (which has average speed of 560 miles) from Linden to Sayreville Junction, It takes 0.02 hours to arrive.
Linden
Linden is located in United States.
| GPS Coordinates (DMS) | 40° 37´ 19.3800'' N 74° 14´ 40.5240'' W |
|---|---|
| Latitude | 40.62205 |
| Longitude | -74.24459 |
| Altitude | 6 m |
| Country | United States |
Linden Distances to Cities
| Linden | Distance |
|---|---|
| Distance from Linden to North Bergen | 28 km |
| Distance from Linden to Weirton | 538 km |
| Distance from Linden to Selden | 106 km |
| Distance from Linden to Roosevelt | 56 km |
| Distance from Linden to Salt Lake City | 3,157 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |