Distance from Laurinburg to Jefferson
Distance from Laurinburg to Jefferson is 497 kilometers. This air travel distance is equal to 309 miles.
The air travel (bird fly) shortest distance between Laurinburg and Jefferson is 497 km or 309 miles.
If you travel with an airplane (which has average speed of 560 miles) from Laurinburg to Jefferson, It takes 0.55 hours to arrive.
Laurinburg
Laurinburg is located in United States.
| GPS Coordinates (DMS) | 34° 46´ 26.5800'' N 79° 27´ 46.1520'' W |
|---|---|
| Latitude | 34.77405 |
| Longitude | -79.46282 |
| Altitude | 69 m |
| Country | United States |
Laurinburg Distances to Cities
Jefferson
Jefferson is located in United States.
| GPS Coordinates | 38° 51´ 52.4160'' N 77° 11´ 15.9360'' W |
|---|---|
| Latitude | 38.86456 |
| Longitude | -77.18776 |
| Altitude | 106 m |
| Country | United States |
Jefferson Distances to Cities
| Jefferson | Distance |
|---|---|
| Distance from Jefferson to Wayne Mi | 647 km |
| Distance from Jefferson to Winthrop | 654 km |
| Distance from Jefferson to San Pedro | 3,704 km |
| Distance from Jefferson to New Berlin | 1,026 km |
| Distance from Jefferson to Frankfort Il | 953 km |