Distance from Lake in the Hills to Sandusky
Distance from Lake in the Hills to Sandusky is 474 kilometers. This air travel distance is equal to 295 miles.
The air travel (bird fly) shortest distance between Lake in the Hills and Sandusky is 474 km or 295 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lake in the Hills to Sandusky, It takes 0.53 hours to arrive.
Lake in the Hills
Lake in the Hills is located in United States.
| GPS Coordinates (DMS) | 42° 10´ 54.0840'' N 88° 19´ 49.2960'' W |
|---|---|
| Latitude | 42.18169 |
| Longitude | -88.33036 |
| Altitude | 270 m |
| Country | United States |
Lake in the Hills Distances to Cities
| Lake in the Hills | Distance |
|---|---|
| Distance from Lake In The Hills to Lemont | 63 km |
| Distance from Lake In The Hills to Rockford | 64 km |
| Distance from Lake In The Hills to Dyer | 102 km |
| Distance from Lake In The Hills to Toledo | 400 km |
| Distance from Lake In The Hills to Southgate | 424 km |
Sandusky
Sandusky is located in United States.
| GPS Coordinates | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
|---|---|
| Latitude | 41.44894 |
| Longitude | -82.70796 |
| Altitude | 183 m |
| Country | United States |
Sandusky Distances to Cities
| Sandusky | Distance |
|---|---|
| Distance from Sandusky to South Euclid | 100 km |
| Distance from Sandusky to Waukesha | 488 km |
| Distance from Sandusky to Pittsburgh | 254 km |
| Distance from Sandusky to Tucson | 2,702 km |
| Distance from Sandusky to Janesville | 540 km |