Distance from Lake Zurich to Romulus
Distance from Lake Zurich to Romulus is 388 kilometers. This air travel distance is equal to 241 miles.
The air travel (bird fly) shortest distance between Lake Zurich and Romulus is 388 km or 241 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lake Zurich to Romulus, It takes 0.43 hours to arrive.
Lake Zurich
Lake Zurich is located in United States.
| GPS Coordinates (DMS) | 42° 11´ 49.0920'' N 88° 5´ 36.2760'' W |
|---|---|
| Latitude | 42.19697 |
| Longitude | -88.09341 |
| Altitude | 268 m |
| Country | United States |
Lake Zurich Distances to Cities
Romulus
Romulus is located in United States.
| GPS Coordinates | 42° 13´ 20.1360'' N 83° 23´ 47.7600'' W |
|---|---|
| Latitude | 42.22226 |
| Longitude | -83.39660 |
| Altitude | 203 m |
| Country | United States |
Romulus Distances to Cities
| Romulus | Distance |
|---|---|
| Distance from Romulus to Minneapolis | 853 km |
| Distance from Romulus to Southfield | 31 km |
| Distance from Romulus to Ithaca | 569 km |
| Distance from Romulus to Sylvania | 62 km |
| Distance from Romulus to Elmira | 545 km |